NEETPhysicsDual Nature of Matter
Photoelectric effect experiments are performed using three different metal plates p, q and r having work functions _p=2.0 eV , _q=2.5 eV and _r=3.0 eV , respectively. A light beam containing wavelengths of 550 ~nm , 450 ~nm and 350 ~nm with equal intensities illuminates each of the plates. The correct I-V graph for the experiment is
Options
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Correct answer
3
Step-by-step solution
gathered 1. K_p=E_p- _p= 1240 550 -20=0.2545 eV K_q=E_q- _q= 1240 450 -25=0.255 eV K_r=E_r- _r= 1240 350 -3.0=0.543 eV gathered In the above equation K represents maximum kinetic energy of photoelectrons and E , the energy of incident right. From the above values we can see that stopping potential, |V_r |> |V_q |> |V_p | Further, their intensities are equal, but energy of individual photon of r is maximum. Hence, number of photons incident (per unit area per unit time) of r can be assumed to be least. Hence, satura