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The variation of stopping potential V 0 as a function of the frequency ( ν ) of the incident light for a metal is shown in figure. The work function of the surface is

Options

  1. A2 . 98 eV
  2. B2 . 07 eV
  3. C1 . 36 eV
  4. D18 . 6 eV

Correct answer

B. 2 . 07 eV

Step-by-step solution

The relation between the stopping potential and the frequency of the incident light is given by e V 0 = h ν - ϕ . . . 1 When V 0 = 0 , ϕ = h ν . . . 2 Substitute the value of the frequency corresponding to zero stopping potential into equation (2) to calculate the required work function of the material. ϕ = 6 . 626 × 10 - 34 J · s × 5 × 10 14 Hz 1 . 6 × 10 - 19 J / eV = 6 . 626 × 5 16 ≈ 2 . 07 eV

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