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NEET
Exam
NEET
Subject
Physics
Chapter
Dual Nature of Matter

NEET · Physics · Dual Nature of Matter

The following graph represents the variation of photocurrent with...

The following graph represents the variation of photocurrent with anode potential for a metal surface. Here I1,I2I_{1}, I_{2} and I3I_{3} represents intensities and γ1,γ2,γ3\gamma_{1}, \gamma_{2}, \gamma_{3} represent frequency for curves 1,2 and 3 respectively, then
The following graph represents the variation of photocurrent with anode potential for a metal surface. Here I_ 1 , I_ 2

Options

  1. Aγ1=γ2\gamma_{1}=\gamma_{2} and I1≠I2I_{1} \neq I_{2}
  2. Bγ1=γ3\gamma_{1}=\gamma_{3} and I1≠I3I_{1} \neq I_{3}
  3. Cγ1=γ2\gamma_{1}=\gamma_{2} and I1=I2I_{1}=I_{2}
  4. Dγ2=γ3\gamma_{2}=\gamma_{3} and I1=I3I_{1}=I_{3}

Correct answer

A. γ1=γ2\gamma_{1}=\gamma_{2} and I1≠I2I_{1} \neq I_{2}

Step-by-step solution

The given figure can be shown as
The following graph represents the variation of photocurrent with anode potential for a metal surface. Here I_ 1 , I_ 2
From figure, we can see that the stopping potential (V0)\left(V_{0}\right) is same for curve 1 and 2. But for curve 3 , it is greater than that for land 2 . As, we know that, eV0=Emax⁡=hγ−ϕ0e V_{0}=E_{\max }=h \gamma-\phi_{0} where, ϕ0\phi_{0} is the work function. Since, V0V_{0} is same for 1 and 2, so from above equation, we have r1=r2r_{1}=r_{2} Thus, for 1,2 and 3 γ1=γ2≠γ3\gamma_{1}=\gamma_{2} \neq \gamma_{3} Also, the saturation current of curve 2 is greater than of curve 1 . But for curve 2 and 3 it is equal, so, I1≠I2=I3I_{1} \neq I_{2}=I_{3}
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