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NEET
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Physics
Chapter
Dual Nature of Matter

NEET · Physics · Dual Nature of Matter

On a photositive surface of threshold wavelength (5 λ), two...

On a photositive surface of threshold wavelength (5 \lambda), two different monochromatic beams of wavelengths (3 \lambda) and (\lambda) are incident, one after another, then match the ratio of physical quantities specified in column - I to the ratio values given in column - II. (
Column IColumn II
(a)Maximum KE of photo electrons(i)1 : 3
(b)Speed of incident photons(ii)1 : 6
(c)Momentum of incident photons(iii)1 : \sqrt{6}
(d)Fastest speeds of photo electrons(iv)1 : 1
) Choose the correct answer from the option given below:On a photositive surface of threshold wavelength (5 λ), two different monochromatic beams of wavelengths (3 λ) and (λ)

Options

  1. A(a) - iii, (b) - ii, (c) - i, (d) - iv
  2. B(a) - ii, (b) - iv, (c) - iii, (d) - i
  3. C(a) - ii, (b) - iv, (c) - i, (d) - iii
  4. D(a) - i, (b) - ii, (c) - iv, (d) - iii

Correct answer

C. (a) - ii, (b) - iv, (c) - i, (d) - iii

Step-by-step solution

On a photositive surface of threshold wavelength (5 λ), two different monochromatic beams of wavelengths (3 λ) and (λ)
K1=hc3λ−hc5λ=hcλ[13−15]=hcλ[215]K2=hcλ−hc5λ=hcλ[1−15]=hcλ[45]\begin{aligned} & \mathrm{K}_1=\frac{\mathrm{hc}}{3 \lambda}-\frac{\mathrm{hc}}{5 \lambda}=\frac{\mathrm{hc}}{\lambda}\left[\frac{1}{3}-\frac{1}{5}\right]=\frac{\mathrm{hc}}{\lambda}\left[\frac{2}{15}\right] \\ & \mathrm{K}_2=\frac{\mathrm{hc}}{\lambda}-\frac{\mathrm{hc}}{5 \lambda}=\frac{\mathrm{hc}}{\lambda}\left[1-\frac{1}{5}\right]=\frac{\mathrm{hc}}{\lambda}\left[\frac{4}{5}\right] \end{aligned}) (a) RatioofofKE (\frac{\mathrm{K}_1}{\mathrm{~K}_2}=\frac{\frac{\mathrm{hc}}{\lambda}\left[\frac{2}{15}\right]}{\frac{\mathrm{hc}}{\lambda}\left[\frac{4}{5}\right]}=\frac{1}{6}=1: 6) (b) Ratio of speeds of incident photons (\frac{c_1}{c_2}=\frac{1}{1}=1: 1) Ratio of momentum of incident photons (\frac{\mathrm{p}_1}{\mathrm{p}_2}=\frac{\lambda_2}{\lambda_1}=\frac{\lambda}{3 \lambda}=1: 3) (c) Ratio of fastest speed of photo electrons (\frac{v_1}{v_2}=\sqrt{\frac{K_1}{K_2}}=\sqrt{\frac{1}{6}}=1: \sqrt{6})$
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