NEETPhysicsDual Nature of Matter
Which of the following values represents the stopping potential when light of frequency 6 × 10 14 Hz is incident on caesium metal with a work function of 2.14 eV?
Options
- A2.48 eV
- B3.52 eV
- C0.34 eV
- D1.18 eV
Correct answer
C. 0.34 eV
Step-by-step solution
Correct Option is : (C) 0.34 eV