NEET
Exam NEET
Subject Physics
Chapter Dual Nature of Matter NEET · Physics · Dual Nature of Matter
Two particles A and B of de Broglie wavelengths λ A and λ B combine...
Two particles A and B of de Broglie wavelengths λA and λB combine to form a particle C. The process conserves momentum. Find the de Broglie wavelength of the particle C. (The motion is one dimensional).
Options A 2 λ A λ B ∣ λ A − λ B ∣ \frac{2{{\lambda }_{A}}{{\lambda }_{B}}}{\left| {{\lambda }_{A}}-{{\lambda }_{B}} \right|} ∣ λ A − λ B ∣ 2 λ A λ B B λ A λ B ∣ λ A − λ B ∣ \frac{{{\lambda }_{A}}{{\lambda }_{B}}}{\left| {{\lambda }_{A}}-{{\lambda }_{B}} \right|} ∣ λ A − λ B ∣ λ A λ B C 2 λ A λ B ∣ 2 λ A − λ B ∣ \frac{2{{\lambda }_{A}}{{\lambda }_{B}}}{\left| 2{{\lambda }_{A}}-{{\lambda }_{B}} \right|} ∣ 2 λ A − λ B ∣ 2 λ A λ B D λ A λ B ∣ 2 λ A − λ B ∣ \frac{{{\lambda }_{A}}{{\lambda }_{B}}}{\left| 2{{\lambda }_{A}}-{{\lambda }_{B}} \right|} ∣ 2 λ A − λ B ∣ λ A λ B Correct answer B. λ A λ B ∣ λ A − λ B ∣ \frac{{{\lambda }_{A}}{{\lambda }_{B}}}{\left| {{\lambda }_{A}}-{{\lambda }_{B}} \right|} ∣ λ A − λ B ∣ λ A λ B
Step-by-step solution
Correct Option is : (B)
λ A λ B ∣ λ A − λ B ∣ \frac{{{\lambda }_{A}}{{\lambda }_{B}}}{\left| {{\lambda }_{A}}-{{\lambda }_{B}} \right|} ∣ λ A − λ B ∣ λ A λ B
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