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NEETPhysicsDual Nature of Matter

Light of frequency exactly equal to the threshold frequency ( ₀ ) of a given photosensitive metal is incident on it. If the intensity of this incident light is now doubled, what will be the maximum kinetic energy of the emitted photoelectrons?

Options

  1. A2h ₀
  2. Bh ₀
  3. CZero
  4. DDepends on the specific value of the work function

Correct answer

C. Zero

Step-by-step solution

According to Einstein's photoelectric equation, the maximum kinetic energy is given by K_ = h - . When the incident frequency is exactly equal to the threshold frequency ( = ₀ ), the energy of the incident photon is exactly equal to the work function ( h ₀ = ). Therefore, K_ = h ₀ - = 0 . The maximum kinetic energy of photoelectrons is strictly independent of the intensity of the incident light. Doubling the intensity only increases the number of photons incident per unit area per unit time. This may increase the n

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