Light of frequency 1.5 ₀ is incident on a photosensitive surface, where ₀ is the threshold frequency of the surface. The stopping potential for the emitted photoelectrons is (where h is Planck's constant and e is the elementary charge):

Step-by-step solution

According to Einstein's photoelectric equation, the maximum kinetic energy is given by: K_ = h - h ₀ The relationship between maximum kinetic energy and stopping potential V₀ is: K_ = eV₀ Substituting the given frequency = 1.5 ₀ into the equation: eV₀ = h(1.5 ₀) - h ₀ eV₀ = 0.5h ₀ eV₀ = h ₀ 2 Rearranging for the stopping potential V₀ : V₀ = h ₀ 2e Using the incident energy instead of kinetic energy leads to the incorrect option 3h ₀ 2e , while forgetting the 0.5 factor leads to h ₀ e . Answer: h ₀ 2e