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NEETPhysicsDual Nature of Matter

In a photoelectric experiment, the stopping potential for a certain metal surface is 1.5 ~V . If the work function of the metal is 2.5 eV , the energy of the incident photons is:

Options

  1. A1.0 eV
  2. B4.0 eV
  3. C4.0 ~V
  4. D1.5 eV

Correct answer

B. 4.0 eV

Step-by-step solution

According to Einstein's photoelectric equation: E = K_ + The maximum kinetic energy K_ in electron-volts is numerically equal to the stopping potential in volts. Thus, for a stopping potential of 1.5 ~V , the maximum kinetic energy is: K_ = 1.5 eV Given the work function = 2.5 eV , the energy of the incident photons is: E = 1.5 eV + 2.5 eV = 4.0 eV Answer: 4.0 eV

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