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Maximum velocity of the photoelectron emitted by a metal is 1.8 10^6 ~m ~s ⁻¹ . Take the value of specific charge of the electron is 1.8 10¹¹ C kg ⁻¹ . Then the stopping potential in volt is

Options

  1. A1
  2. B3
  3. C9
  4. D6

Correct answer

C. 9

Step-by-step solution

In photoelectic effect stopping potenital is given by V_S= 1 2 m e v_ ^2 Here, aligned & e m =1.8 10¹¹ C kg ⁻¹, v_ =1.8 10^6 ~m ~s ⁻¹ & V_S= 1 2 1 1.8 10¹¹ (1.8 10^6 )^2=9 ~V aligned

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