NEET2014PhysicsDual Nature of MatterActual
The light of wavelength 4000 Å falls on a photosensitive substance whose work function is 2 eV . Its stopping potential is
Options
- A1.1 ~V
- B1.8 ~V
- C1.26 ~V
- D0.8 ~V
Correct answer
A. 1.1 ~V
Step-by-step solution
As K_ = h c - ₀=3.1 eV -2 eV =1.1 eV V₀=1.1 ~V