If velocity of a particle is three times of that of electron and ratio of de Broglie wavelength of particle to that of electron is 1.814 10⁻⁴ . The particle will be

Step-by-step solution

de brogile wavelength, = h p or = h m v _p _e = m_e v_e m_p v_p m_p= m_e v_e v_p _e _p Here, m_e=9.1 10⁻³¹ ~kg , v_p=3 v_e and _p _e =1.814 10⁻⁴ m_p= 9.1 10⁻³¹ 1.814 10⁻⁴ 3 =1.672 10⁻²⁷ ~kg Thus, the particle is neutron.