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NEETChemistryClassification of Elements and Periodicity in Properties

Match List- I with List- II . List- I Electronic configuration of elements List- II Δ i H in kJ mol - 1 a 1 s 2 2 s 2 p 801 b 1 s 2 2 s 2 2 p 4 q 899 c 1 s 2 2 s 2 2 p 3 r 1314 d 1 s 2 2 s 2 2 p 1 s 1402 Choose the most appropriate answer from the options given below:

Options

  1. Aa → q , b → r , c → s , d → p
  2. Ba → p , b → r , c → s , d → q
  3. Ca → p , b → s , c → r , d → q
  4. Da → s , b → p , c → q , d → r

Correct answer

A. a → q , b → r , c → s , d → p

Step-by-step solution

(a) 1 s 2 2 s 2 → Be (b) 1 s 2 2 s 2 2 p 4 → O (c) 1 s 2 2 s 2 2 p 3 → N (d) 1 s 2 2 s 2 2 p 1 → B The ionization enthalpy order is B < Be < O < N Be has more IE compared to B due to extra stability & N has more IE compared to oxygen due to extra stability Hence, N → 1402 kJ mol - 1 O → 1314 kJ mol - 1 B → 801 kJ mol - 1 Be → 899 kJ mol - 1

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