NEETChemistryClassification of Elements and Periodicity in Properties
Match List-I with List-II. List-I (Successive Ionization Enthalpies in kJ mol ⁻¹ ) List-II (Classification) (P) IE ₁ = 520, IE ₂ = 7300, IE ₃ = 11815 (i) Reactive non-metal (Q) IE ₁ = 2372, IE ₂ = 5251, IE ₃ = 6280 (ii) Noble gas (R) IE ₁ = 1681, IE ₂ = 3374, IE ₃ = 6050 (iii) Alkali metal (S) IE ₁ = 900, IE ₂ = 1757, IE ₃ = 14848 (iv) Alkaline earth metal Choose the correct answer from the options given below:
Options
- A(P)-(iv), (Q)-(i), (R)-(ii), (S)-(iii)
- B(P)-(iii), (Q)-(ii), (R)-(i), (S)-(iv)
- C(P)-(iii), (Q)-(i), (R)-(ii), (S)-(iv)
- D(P)-(i), (Q)-(ii), (R)-(iii), (S)-(iv)
Correct answer
B. (P)-(iii), (Q)-(ii), (R)-(i), (S)-(iv)
Step-by-step solution
The difference between successive ionization enthalpies helps identify the number of valence electrons and the chemical nature of the element. For P: There is a massive jump between IE ₁ and IE ₂ (from 520 to 7300 kJ mol ⁻¹ ). This indicates the removal of the second electron disrupts a stable noble gas core. Thus, P has 1 valence electron and is an Alkali metal (iii). For Q: The first ionization enthalpy is exceptionally high ( 2372 kJ mol ⁻¹ ) with no sudden proportional jump in the first three values. This is ch