NEETChemistryClassification of Elements and Periodicity in Properties
Match the compounds in List I with their dominant redox behaviour in List II based on the inert pair effect. List I List II A. PbO ₂ I. Strong reducing agent B. SnCl ₂ II. Strong oxidizing agent (due to +4 +2 transition) C. TlCl ₃ III. Strong oxidizing agent (due to +3 +1 transition) D. AlCl ₃ IV. Highly stable in its current oxidation state Choose the correct answer from the options given below:
Options
- AA-II, B-III, C-I, D-IV
- BA-II, B-I, C-III, D-IV
- CA-I, B-II, C-III, D-IV
- DA-III, B-I, C-II, D-IV
Correct answer
B. A-II, B-I, C-III, D-IV
Step-by-step solution
The inert pair effect causes the lower oxidation state to become more stable down the group in p-block elements. A. PbO ₂ : Pb is in the +4 state. Since +2 is more stable for the heavier Pb, it readily accepts electrons to form Pb ²⁺ , acting as a strong oxidizing agent (Match II). B. SnCl ₂ : Sn is in the +2 state. Since +4 is more stable for the lighter Sn, it readily loses electrons to form Sn ⁴⁺ , acting as a strong reducing agent (Match I). C. TlCl ₃ : Tl is in the +3 state. Since +1 is more stable for the hea