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NEETChemistryClassification of Elements and Periodicity in Properties

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): Aluminium can form the complex ion [AlF₆]³⁻ but boron cannot form [BF₆]³⁻ . Reason (R): Aluminium has 9 valence orbitals in its valence shell whereas boron has only 4 valence orbitals. In the light of the above statements, choose the most appropriate answer from the options given below:

Options

  1. ABoth (A) and (R) are correct and (R) is the correct explanation of (A)
  2. BBoth (A) and (R) are correct but (R) is not the correct explanation of (A)
  3. C(A) is correct but (R) is not correct
  4. D(A) is not correct but (R) is correct

Correct answer

A. Both (A) and (R) are correct and (R) is the correct explanation of (A)

Step-by-step solution

Assertion (A) is correct: Aluminium belongs to the third period and can expand its covalency beyond 4 to form octahedral complexes like [AlF₆]³⁻ . Boron belongs to the second period and is restricted to a maximum covalency of 4 , so it cannot form [BF₆]³⁻ . Reason (R) is correct and explains (A): The valence shell of boron ( n=2 ) consists of only four orbitals (one 2s and three 2p ). Due to the absence of d -orbitals, its maximum covalency is 4 . The valence shell of aluminium ( n=3 ) contains nine orbitals (one 3

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