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NEETChemistryStates of Matter

Pressure of 1 g of an ideal gas A at 27 °C is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature the pressure becomes 3 bar. What is the relationship between their molecular masses?

Options

  1. A[Molar mass of B] = 3 × [Molar mass of A]
  2. B[Molar mass of B] = 4 × [Molar mass of A]
  3. C[Molar mass of B] = 5 × [Molar mass of A]
  4. D[Molar mass of B] = 6 × [Molar mass of A]

Correct answer

B. [Molar mass of B] = 4 × [Molar mass of A]

Step-by-step solution

Correct Option is : (B) [Molar mass of B] = 4 × [Molar mass of A]

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