NEETChemistryThermodynamics (C)
The isotherms of an ideal gas at T₁, T₂, T₃ along with their slopes (m) (in the brackets) are shown here. If T₁>T₂>T₃ , then the correct order of slopes of these isotherms is
Options
- Am₂>m₁>m₃
- Bm₃>m₂>m₁
- Cm ₂> m ₃> m ₁
- Dm ₁> m ₂> m ₃
Correct answer
D. m ₁> m ₂> m ₃
Step-by-step solution
P = nRT 1 ~V ( y = mx + c where c =0) Thus, a higher value of T would increase the value of the slope of the P vs. 1 ~V curve. Therefore, the correct order of slopes would be: m ₁> m ₂> m ₃