Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R Assertion A : The reduction of a metal oxide is easier if the metal formed is in liquid state than solid state. Reason R : The value of ΔG Θ becomes more on negative side as entropy is higher in liquid state than solid state. In the light of the above statements. Choose the most appropriate answer from the options giv

Step-by-step solution

The entropy is higher if the metal is in liquid state than when it is in solid state. The value of entropy change ( ∆ S ) of the reduction process is more on positive side when the metal formed is in liquid state and the metal oxide being reduced is in solid state. Thus the value of ∆ f G becomes more on negative side and the reduction becomes easier. ΔG = ΔH - TΔS ∵ Entropy of liquid is more than solid ∴ on melting the entropy increases and ΔG becomes more negative and hence it becomes easier to reduce metal.