NEETChemistryThermodynamics (C)
Calculate the standard enthalpy of formation of CH 3 OH(l) from the following data: CH 3 OH (l) + 3/2 O 2 (g) → CO 2 (g) + 2H 2 O(l) ; ∆ r H ⊖ = –726 kJ mol –1 C(graphite) + O 2 (g) → CO 2 (g) ; ∆ c H ⊖ = –393 kJ mol –1 H 2 (g) + 1/2 O 2 (g) → H 2 O(l) ; ∆ f H ⊖ = –286 kJ mol –1
Options
- A–390 kJ mol –1
- B–265 kJ mol –1
- C–324 kJ mol –1
- D–239 kJ mol –1
Correct answer
D. –239 kJ mol –1
Step-by-step solution
Correct Option is : (D) –239 kJ mol –1