Calculate the enthalpy change for the process: CCl 4 (g) → C(g) + 4Cl(g) and calculate bond enthalpy of C–Cl in CCl 4 (g). ∆ vap H ⊖ (CCl 4 ) = 30.5 kJ mol –1 ; ∆ f H ⊖ (CCl 4 ) = –135.5 kJ mol –1 . ∆ a H ⊖ (C) = 715.0 kJ mol –1 , where ∆ a H is enthalpy of atomisation ∆ a H ⊖ (Cl 2 ) = 242 kJ mol –1