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NEETChemistryThermodynamics (C)

The value of ∆ f H ⊖ for NH 3 is – 91.8 kJ mol –1 . Calculate enthalpy change for the following reaction : 2NH 3 (g) → N 2 (g) + 3H 2 (g)

Options

  1. A∆ r H ⊖ = -83.6 kJ mol –1
  2. B∆ r H ⊖ = -91.8 kJ mol –1
  3. C∆ r H ⊖ = +83.6 kJ mol –1
  4. D∆ r H ⊖ = +91.8 kJ mol –1

Correct answer

D. ∆ r H ⊖ = +91.8 kJ mol –1

Step-by-step solution

Correct Option is : (D) ∆ r H ⊖ = +91.8 kJ mol –1

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