NEETChemistryThermodynamics (C)
If the combustion of 1g of graphite produces 20.7 kJ of heat, what will be molar enthalpy change? Give the significance of sign also.
Options
- A∆H = – 2.48 × 10 3 kJmol –1 , Negative value of ∆H ⇒ exothermic rxn
- B∆H = – 2.48 × 10 2 kJmol –1 , Negative value of ∆H ⇒ exothermic reaction
- C∆H = – 2.48 × 10 2 kJmol –1 , Negative value of ∆H ⇒ endothermic reaction
- D∆H = – 3.67 × 10 2 kJmol –1 , Negative value of ∆H ⇒ exothermic reaction
Correct answer
B. ∆H = – 2.48 × 10 2 kJmol –1 , Negative value of ∆H ⇒ exothermic reaction
Step-by-step solution
Correct Option is : (B) ∆H = – 2.48 × 10 2 kJmol –1 , Negative value of ∆H ⇒ exothermic reaction