Match List I with List II. List I (Process) List II (Thermodynamic signs) A. Freezing of water at 260 K 1. H B. Melting of ice at 290 K 2. H > 0 , S > 0 , G C. Freezing of water at 280 K 3. H 0 D. Melting of ice at 260 K 4. H > 0 , S > 0 , G > 0 Choose the correct answer from the options given below:

Step-by-step solution

For the freezing of water (liquid solid), heat is released ( H At 260 K (below the freezing point), freezing is spontaneous, so G At 280 K (above the freezing point), freezing is non-spontaneous, so G > 0 . This matches C with 3. For the melting of ice (solid liquid), heat is absorbed ( H > 0 ) and randomness increases ( S > 0 ). At 290 K (above the melting point), melting is spontaneous, so G At 260 K (below the melting point), melting is non-spontaneous, so G > 0 . This matches D with 4. Therefore, the correct ma