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NEETChemistryThermodynamics (C)

An ideal gas undergoes isothermal compression from 2.5 L to 1.0 L . If the work done on the gas during this process is 150 J , what is the constant external pressure applied? (Given: 1 L bar = 100 J )

Options

  1. A1.0 bar
  2. B100 bar
  3. C-1.0 bar
  4. D10 bar

Correct answer

A. 1.0 bar

Step-by-step solution

Work done on the gas is positive, so W = +150 J . Converting Joules to L bar : W = 150 100 = 1.5 L bar The formula for work done against a constant external pressure is: W = -P_ ext (V_ f - V_ i ) Substituting the given values: 1.5 = -P_ ext (1.0 - 2.5) 1.5 = -P_ ext (-1.5) P_ ext = 1.0 bar Answer: 1.0 bar

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