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NEET2018ChemistryThermodynamics (C)Actual

For the following reaction, Then, K _ e 0 for this equilibrium is

Options

  1. A-3.41
  2. B2.38
  3. C120
  4. D1500

Correct answer

B. 2.38

Step-by-step solution

Given, aligned G ^ & =-13.6 ~kJ ~mol ⁻¹ ~T & =298 ~K aligned For equilibrium, the Gibb's free energy is calculated by using the formula. G ^ =-2.303 RT K _ eq or, K _ eq =- G ^ 2.303 RT =- -13.6 10^3 ~J ~mol ⁻¹ 2.303 8.314 ~J ~mol ⁻¹ ~K ⁻¹ 298 ~K =2.38

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