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NEETChemistryIonic Equilibrium

What is the equilibrium constant (K b ) for the base-dissociation equilibrium reaction mentioned in the paragraph?

Options

  1. AKb = [BH+][OH-] / [B]
  2. BKb = [BH+][OH-]
  3. CKb = [B] / [OH-]
  4. DKb = [BH+][B]

Correct answer

A. Kb = [BH+][OH-] / [B]

Step-by-step solution

The equilibrium constant (K b ) for the base-dissociation equilibrium reaction is K b = [BH+][OH+] / [B].

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