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NEETChemistryIonic Equilibrium

The pH of 0.005M codeine (C 18 H 21 NO 3 ) solution is 9.95. Calculate its ionization constant and pKb.

Options

  1. AKb = 0.0158 × 10 -4 , pKb = 5.80
  2. BKb = 2.51 × 10 -5 , pKb = 4.60
  3. CKb = 5.01 × 10 -6 , pKb = 4.30
  4. DKb = 6.01 × 10 -6 , pKb = 4.80

Correct answer

A. Kb = 0.0158 × 10 -4 , pKb = 5.80

Step-by-step solution

Correct Option is : (A) Kb = 0.0158 × 10 -4 , pKb = 5.80

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