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NEETChemistryIonic Equilibrium

The solubility of Sr(OH) 2 at 298 K is 19.23 g/L of solution. Calculate the concentrations of strontium and hydroxyl ions and the pH of the solution.

Options

  1. A[Sr 2+ ] = 0.15 M, [OH - ] = 0.31 M, pH = 13.50
  2. B[Sr 2+ ] = 0.08 M, [OH - ] = 0.16 M, pH = 12.00
  3. C[Sr 2+ ] = 0.16 M, [OH - ] = 0.08 M, pH = 12.60
  4. D[Sr 2+ ] = 0.04 M, [OH - ] = 0.02 M, pH = 13.80

Correct answer

A. [Sr 2+ ] = 0.15 M, [OH - ] = 0.31 M, pH = 13.50

Step-by-step solution

Correct Option is : (A) [Sr 2+ ] = 0.15 M, [OH - ] = 0.31 M, pH = 13.50

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