NEETChemistryIonic Equilibrium
The ionization constant of nitrous acid is 4.5 × 10 -4 . Calculate the pH of 0.04 M sodium nitrite solution and also its degree of hydrolysis.
Options
- ApH = 8.00, Degree of hydrolysis (α) = 0.0000023
- BpH = 3.50, Degree of hydrolysis (α) = 0.0000009
- CpH = 3.20, Degree of hydrolysis (α) = 0.0000012
- DpH = 3.10, Degree of hydrolysis (α) = 0.0000012
Correct answer
A. pH = 8.00, Degree of hydrolysis (α) = 0.0000023
Step-by-step solution
Correct Option is : (A) pH = 8.00, Degree of hydrolysis (α) = 0.0000023