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NEETChemistryIonic Equilibrium

The solubility product constant of Ag 2 CrO 4 and AgBr are 1.1 × 10 -12 and 5.0 × 10 -13 respectively. Calculate the ratio of the molarities of their saturated solutions.

Options

  1. A[Ag 2 CrO 4 ] / [AgBr] = 0.22
  2. B[Ag 2 CrO 4 ] / [AgBr] = 0.20
  3. C[Ag 2 CrO 4 ] / [AgBr] = 92
  4. D[Ag 2 CrO 4 ] / [AgBr] = 2.2

Correct answer

C. [Ag 2 CrO 4 ] / [AgBr] = 92

Step-by-step solution

Correct Option is : (C) [Ag 2 CrO 4 ] / [AgBr] = 92

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