Match List-I with List-II. Given: Solubility product ( K_ sp ) of AgCl = 10⁻¹⁰ and K_ sp of Ag₂CrO₄ = 4 10⁻¹² . List-I List-II (Molar solubility in M) (A) AgCl in water (I) 10⁻⁹ (B) AgCl in 0.1 M KCl (II) 10⁻⁴ (C) Ag₂CrO₄ in water (III) 4 10⁻¹⁰ (D) Ag₂CrO₄ in 0.1 M AgNO ₃ (IV) 10⁻⁵ Choose the correct answer from the options given below:

Step-by-step solution

(A) For AgCl in water: K_ sp = s² s = 10⁻¹⁰ = 10⁻⁵ M . This matches (IV). (B) For AgCl in 0.1 M KCl : K_ sp = s [ Cl ⁻] 10⁻¹⁰ = s 0.1 s = 10⁻⁹ M . This matches (I). (C) For Ag₂CrO₄ in water: K_ sp = 4s³ 4 10⁻¹² = 4s³ s³ = 10⁻¹² s = 10⁻⁴ M . This matches (II). (D) For Ag₂CrO₄ in 0.1 M AgNO ₃ : K_ sp = [ Ag ⁺]²[ CrO₄²⁻ ] 4 10⁻¹² = (0.1)² s s = 4 10⁻¹⁰ M . This matches (III). Therefore, the correct matching is (A)-(IV), (B)-(I), (C)-(II), (D)-(III). Answer: (A)-(IV), (B)-(I), (C)-(II), (D)-(III)