NEETChemistryIonic Equilibrium
Match List I with List II: List I (Metal hydroxide and K_ sp ) List II ( [ OH ^-] in saturated solution) (A) MOH , K_ sp = 10⁻¹⁰ (I) 3 10⁻⁴ M (B) M(OH) ₂ , K_ sp = 4 10⁻¹² (II) 4 10⁻⁵ M (C) M(OH) ₃ , K_ sp = 2.7 10⁻¹⁵ (III) 10⁻⁵ M (D) M ' (OH) ₂ , K_ sp = 3.2 10⁻¹⁴ (IV) 2 10⁻⁴ M Choose the correct answer from the options given below:
Options
- A(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
- B(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- C(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
- D(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
Correct answer
B. (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
Step-by-step solution
For MOH : K_ sp = s^2 = 10⁻¹⁰ s = 10⁻⁵ M . [ OH ^-] = s = 10⁻⁵ M . (A matches III) For M(OH) ₂ : K_ sp = 4s^3 = 4 10⁻¹² s^3 = 10⁻¹² s = 10⁻⁴ M . [ OH ^-] = 2s = 2 10⁻⁴ M . (B matches IV) For M(OH) ₃ : K_ sp = 27s^4 = 2.7 10⁻¹⁵ = 27 10⁻¹⁶ s^4 = 10⁻¹⁶ s = 10⁻⁴ M . [ OH ^-] = 3s = 3 10⁻⁴ M . (C matches I) For M ' (OH) ₂ : K_ sp = 4s^3 = 3.2 10⁻¹⁴ = 32 10⁻¹⁵ s^3 = 8 10⁻¹⁵ s = 2 10⁻⁵ M . [ OH ^-] = 2s = 4 10⁻⁵ M . (D matches II) Therefore, the correct matching is (A)-(III), (B)-(IV), (C)-(I), (D)-(II). Answer: (A)-(III)