NEETChemistryIonic Equilibrium
Match the acid-base mixtures in List I with the nature of the resulting solution in List II. (A) 100 mL of 0.1 M CH ₃ COOH + 50 mL of 0.1 M NaOH (I) Acidic buffer (B) 100 mL of 0.1 M NH ₄ OH + 100 mL of 0.1 M HCl (II) Basic salt solution (C) 100 mL of 0.1 M HCl + 100 mL of 0.1 M NaOH (III) Acidic salt solution (D) 100 mL of 0.1 M CH ₃ COOH + 100 mL of 0.1 M NaOH (IV) Neutral solution Choose the correct answer from th
Options
- A(A)-(I), (B)-(III), (C)-(IV), (D)-(II)
- B(A)-(I), (B)-(II), (C)-(IV), (D)-(III)
- C(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
- D(A)-(I), (B)-(III), (C)-(II), (D)-(IV)
Correct answer
A. (A)-(I), (B)-(III), (C)-(IV), (D)-(II)
Step-by-step solution
Calculate the millimoles of acid and base for each mixture: (A) 10 mmol CH ₃ COOH + 5 mmol NaOH 5 mmol CH ₃ COOH + 5 mmol CH ₃ COONa . This is a mixture of a weak acid and its salt with a strong base, forming an acidic buffer (I). (B) 10 mmol NH ₄ OH + 10 mmol HCl 10 mmol NH ₄ Cl . Complete neutralization forms the salt of a weak base and strong acid, which undergoes cationic hydrolysis to give an acidic salt solution (III). (C) 10 mmol HCl + 10 mmol NaOH 10 mmol NaCl . Complete neutralization forms the salt of a s