NEET2002ChemistryIonic EquilibriumActual
If the solubility of MX ₂ type electrolyte is 0.5 10⁻⁴ ~mol ~L ⁻¹ , then, find out K _ s p of the electrolyte.
Options
- A5 10⁻¹²
- B25 10⁻¹⁰
- C1 10⁻¹³
- D5 10⁻¹³
Correct answer
D. 5 10⁻¹³
Step-by-step solution
An electrolyte ( MX ₂ ) undergoes dissociation as follows :- ( MX ₂ M ⁺²+2 X ⁻ ) ( array |c|c|c|c| Concentration & MX ₂ & M ⁺² & X ⁻ Initial concentration & 1 & 0 & 0 Concentration at Equilibrium & 1- s & s & 2 ~s array ) Thus from the above condition we can say that, ( K _ sp = s (2 ~s )^2=4 ( s )^3 ) Here, s (the solubility) is (0.5 10⁻⁴ ~mole / lit ). ( aligned & K _ sp =4 (0.5 10⁻⁴ )^3 & K _ sp =5 10⁻¹³ aligned )