NEET2005ChemistryIonic EquilibriumActual
When 10 ~mL of 0.1 M acetic acid ( p K_a=5.0 ) is titrated against 10 ~mL of 0.1 M ammonia solution ( p K_b=5.0 ), the equivalence point occurs at pH
Options
- A5.0
- B6.0
- C7.0
- D9.0
Correct answer
C. 7.0
Step-by-step solution
: p K_a=- K_a, p K_b=- K_b aligned pH & =- 1 2 [ K_a+ K_w- K_b ] & =- 1 2 [5 (1 10⁻¹⁴ )-(5) ] & =- 1 2 [5-14-5]=- 1 2 (-14)=7 aligned