10⁻⁶ M~ NaOH is diluted 100 times. The pH of the

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[ OH ⁻ ] in the diluted base = 10⁻⁶ 10^2 =10⁻⁸ aligned Total [ OH ⁻ ] & =10⁻⁸+ [ OH ⁻ ] of water & = (10⁻⁸+10⁻⁷ ) M & =10⁻⁸[1+10] M & =11 10⁻⁸ M pOH & =- (11 10⁻⁸ ) & =- 11+8 10 & =6.9586 pH & =14-6.9586 & =7.0414 aligned