NEET2010ChemistryIonic EquilibriumActual
The solubility of saturated solution of Ag ₂ CrO ₄ is s mol L ⁻¹ . What is its solubility product?
Options
- A4 s^3
- Bs^3
- C2 s^3
- D16 s^2
Correct answer
A. 4 s^3
Step-by-step solution
Ag ₂ CrO ₄ ionises completely in the solution as s ~mol / L Ag ₂ CrO ₄ 2 s ~mol / L 2 Ag ⁺ + s ~mol / L CrO ₄²⁻ Hence, the solubility product, aligned K_ sp of Ag ₂ CrO ₄ & = [ Ag ⁺ ]^2 [ CrO ₄²⁻ ] & =(2 s)^2(s) & =4 s^3 aligned