NEET2009ChemistryIonic EquilibriumActual
A 0.1 aqueous solution of a weak acid is 2 % ionised. If the ionic product of water is 1 10⁻¹⁴ , the [ OH ⁻ ] is
Options
- A5 10⁻¹² M
- B2 10⁻³ M
- C1 10⁻¹⁴ M
- DNone of these
Correct answer
A. 5 10⁻¹² M
Step-by-step solution
Since, it is a weak acid, the equation to calculate [ H ⁺ ] is aligned & =C ( = % of ionisation ) & =0.1 0.02=2 10⁻³ M K_w & = [ H ⁺ ] [ OH ⁻ ] [ OH ⁻ ] & = K_w [ H ⁺ ] = 1 10⁻¹⁴ 2 10⁻³ & =5 10⁻¹² M aligned