NEET2004ChemistryIonic EquilibriumActual
The pH of 10⁻⁸ M NaOH is
Options
- A8.0
- B6.0
- C6.96
- D7.04
Correct answer
D. 7.04
Step-by-step solution
For 10⁻⁸ M NaOH , [ OH ⁻ ]=10⁻⁸+10⁻⁷ (from water) =11 10⁻⁸ pOH =- [ OH ⁻ ]=- (11 10⁻⁸)=8-1.04=6.96 pH =14-6.96=7.04