NEETChemistrySolutions
6.3 g of oxalic acid dihydrate ( H₂C₂O₄ 2H₂O ) is dissolved in water to prepare an M 10 aqueous solution. The volume of the resulting solution is :
Options
- A500 mL
- B700 mL
- C0.5 mL
- D5 mL
Correct answer
A. 500 mL
Step-by-step solution
First, calculate the molar mass of oxalic acid dihydrate ( H₂C₂O₄ 2H₂O ): Molar mass = (2 1) + (2 12) + (4 16) + 2 (2 1 + 16) Molar mass = 2 + 24 + 64 + 36 = 126 g mol ⁻¹ Number of moles of solute ( n ): n = Given mass Molar mass = 6.3 126 = 0.05 mol The given molarity is M 10 = 0.1 M . Molarity ( M ) is given by: M = n V (in L) 0.1 = 0.05 V V = 0.05 0.1 = 0.5 L Converting the volume to mL: V = 0.5 1000 mL = 500 mL Answer: 500 mL