NEETChemistrySolutions
Match List I with List II. List I (Mixture) List II (Property/Nature) A. Bromoethane and Chloroethane I. _ mix H > 0 , _ mix V > 0 B. Ethanol and Acetone II. _ mix H C. Chloroform and Acetone III. _ mix H = 0 , _ mix V = 0 D. 68 % Nitric acid and 32 % Water by mass IV. Maximum boiling azeotrope Choose the correct answer from the options given below:
Options
- AA-III, B-I, C-II, D-IV
- BA-III, B-II, C-I, D-IV
- CA-I, B-III, C-IV, D-II
- DA-II, B-I, C-IV, D-III
Correct answer
A. A-III, B-I, C-II, D-IV
Step-by-step solution
A. Bromoethane and chloroethane form an ideal solution. For an ideal solution, _ mix H = 0 and _ mix V = 0 . B. Ethanol and acetone form a non-ideal solution showing positive deviation from Raoult's law. For such solutions, _ mix H > 0 and _ mix V > 0 . C. Chloroform and acetone form a non-ideal solution showing negative deviation from Raoult's law due to intermolecular hydrogen bonding. For such solutions, _ mix H D. A mixture of 68 % nitric acid and 32 % water by mass forms a maximum boiling azeotrope, as it show