The molality of an aqueous solution of a non-volatile solute is 5.55 m . The mole fraction of the solute in this solution is approximately:

Step-by-step solution

A molality of 5.55 m means that there are 5.55 moles of the solute dissolved in 1 kg ( 1000 g ) of the solvent (water). Moles of solute ( n₂ ) = 5.55 mol Mass of water = 1000 g Molar mass of water = 18 g mol ⁻¹ Moles of solvent ( n₁ ) = 1000 18 55.55 mol Total moles in the solution = n₁ + n₂ = 55.55 + 5.55 = 61.10 mol Mole fraction of the solute ( x₂ ) = n₂ n₁ + n₂ x₂ = 5.55 61.10 0.0908 Rounding to three decimal places, the mole fraction is approximately 0.091 . Answer: 0.091