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When chloroform and acetone are mixed, they form a non-ideal solution. Which of the following correctly describes the type of deviation from Raoult's law and the thermodynamic properties of this mixture?

Options

  1. APositive deviation, _ mix H > 0 , _ mix V > 0
  2. BNegative deviation, _ mix H > 0 , _ mix V < 0
  3. CNegative deviation, _ mix H < 0 , _ mix V < 0
  4. DIdeal solution, _ mix H = 0 , _ mix V = 0

Correct answer

C. Negative deviation, _ mix H < 0 , _ mix V < 0

Step-by-step solution

When chloroform and acetone are mixed, a hydrogen bond is formed between the highly polarized carbon-hydrogen bond of chloroform and the oxygen atom of acetone. This makes the intermolecular (A-B) interactions stronger than the pure component (A-A and B-B) interactions. Consequently, the escaping tendency of molecules decreases, leading to a negative deviation from Raoult's law. For solutions showing negative deviation, the stronger interactions lead to a release of energy ( _ mix H Answer: Negative deviation, _ mi

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