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AIIMS2006ChemistryThermodynamics (C)

The enthalpy change ( H) for the reaction, N _ 2( ~g ) +3 H _ 2( ~g ) 2 NH _ 3( ~g ) is -92.38 ~kJ at 298 ~K . The internal energy change U at 298 ~K is

Options

  1. A-92.38 ~kJ
  2. B-87.42 ~kJ
  3. C-97.34 ~kJ
  4. D-89.9 ~kJ .

Correct answer

B. -87.42 ~kJ

Step-by-step solution

H= U+ n R T [where n= no. of molecules of products - no. of molecules of reactants] or, -92.38 1000= U-2 8.314 298 or, U=-87424 ~J =-87.424 ~kJ .

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