The heat of neutralization of a strong base and a strong acid is 57 ~kJ . The heat released when 0.5 mole of HNO_3 solution is added to 0.20 moles of NaOH solution, is

Correct answer: A. 11.4 ~kJ Heat of neutralization (Δ H)=57 ~kJ , mole of HNO_3=0.5 mole and mole of NaOH=0.2 mole. When HNO_3 solution is added to NaOH solution, then 0.2 mole of HNO_3 solution will combine with 0.2 mole of OH^ - ions of NaOH solution. Heat released =Δ H × 0.2=57 × 0.2=11.4 ~kJ .

AIIMS 2002

Exam: AIIMS
Year: 2002
Subject: Chemistry
Chapter: Thermodynamics (C)

AIIMS 2002 · Chemistry · Thermodynamics (C)

The heat of neutralization of a strong base and a strong acid is 57...

The heat of neutralization of a strong base and a strong acid is

57 \mathrm{~kJ}

. The heat released when 0.5 mole of

\mathrm{HNO}_3

solution is added to 0.20 moles of

\mathrm{NaOH}

solution, is

Options

A $11.4 \mathrm{~kJ}$
B $34.7 \mathrm{~kJ}$
C $23.5 \mathrm{~kJ}$
D $58.8 \mathrm{~kJ}$ .

Correct answer

A. $11.4 \mathrm{~kJ}$

Step-by-step solution

Heat of neutralization

(\Delta H)=57 \mathrm{~kJ}

, mole of

\mathrm{HNO}_3=0.5

mole and mole of

\mathrm{NaOH}=0.2

mole. When

\mathrm{HNO}_3

solution is added to

\mathrm{NaOH}

solution, then 0.2 mole of

\mathrm{HNO}_3

solution will combine with 0.2 mole of

\mathrm{OH}^{-}

ions of

\mathrm{NaOH}

solution.

\therefore \quad

Heat released

=\Delta H \times 0.2=57 \times 0.2=11.4 \mathrm{~kJ}

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