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AIIMS 201926 May
Exam
AIIMS
Year
2019
Date
26 May
Subject
Physics
Chapter
Alternating Current

AIIMS 2019 · 26 May · Physics · Alternating Current

In LCR series circuit, source voltage is 120 ~V and voltage across...

In LCR series circuit, source voltage is 120 V120 \mathrm{~V} and voltage across inductor 50 V50 \mathrm{~V}. If voltage drop across resistance is 40 V40 \mathrm{~V}, then determine voltage in capacitor.In LCR series circuit, source voltage is 120 ~V and voltage across inductor 50 ~V . If voltage drop across resistance

Options

  1. A10(5−82)V10(5-8 \sqrt{2}) \mathrm{V}
  2. B10(5+82)V10(5+8 \sqrt{2}) \mathrm{V}
  3. C20(5+82)V20(5+8 \sqrt{2}) \mathrm{V}
  4. D10(5+72)V10(5+7 \sqrt{2}) \mathrm{V}

Correct answer

B. 10(5+82)V10(5+8 \sqrt{2}) \mathrm{V}

Step-by-step solution

In LCR series circuit, source voltage is 120 ~V and voltage across inductor 50 ~V . If voltage drop across resistance
1202=402+(VC−50)2VC=408+50=10(5+82)V\begin{aligned} & 120^2=40^2+\left(V_C-50\right)^2 \\ & V_C=40 \sqrt{8}+50=10(5+8 \sqrt{2}) \mathrm{V}\end{aligned}
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