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AIIMS 2012
Exam
AIIMS
Year
2012
Subject
Physics
Chapter
Alternating Current

AIIMS 2012 · Physics · Alternating Current

In a given series L C R circuit R=4 , X_L=5 and X_C=8 , the current

In a given series LCRL C R circuit R=4Ω,XL=5ΩR=4 \Omega, X_L=5 \Omega and XC=8ΩX_C=8 \Omega, the current

Options

  1. ALeads the voltage by tan⁡−1(3/4)\tan ^{-1}(3 / 4).
  2. BLeads the voltage by tan⁡−1(5/8)\tan ^{-1}(5 / 8).
  3. CLags the voltage by tan⁡−1(3/4)\tan ^{-1}(3 / 4).
  4. DLags the voltage by tan⁡−1(5/8)\tan ^{-1}(5 / 8).

Correct answer

A. Leads the voltage by tan⁡−1(3/4)\tan ^{-1}(3 / 4).

Step-by-step solution

The phase angle θ=tan⁡−1(XC−XLR)\theta=\tan ^{-1}\left(\frac{X_C-X_L}{R}\right)=\tan ^{-1}\left(\frac{8-5}{4}\right)θ=tan⁡−1(34)\theta=\tan ^{-1}\left(\frac{3}{4}\right) Therefore, the current leads the voltage by tan⁡−1(34)\tan ^{-1}\left(\frac{3}{4}\right)
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