NEET
- Exam
- NEET
- Subject
- Chemistry
- Chapter
- Carboxylic Acid Derivatives
NEET · Chemistry · Carboxylic Acid Derivatives
Given below are two statements: Statement-I : The reaction of...
Given below are two statements:
Statement-I : The reaction of alcohol with carboxylic acid is carried out in presence of small amount of concentrated sulphuric acid. This reaction is reversible and therefore, water is removed as soon as it formed.
Statement-II : Reaction of alcohol with acid chloride is carried in presence of base (pyridine) which do not neutralize HCl which is formed during the reaction.
In the light of the above statements, choose the most appropriate answer from the options given below:
Options
- ABoth statement I and statement II are incorrect.
- BStatement I is incorrect but statement II is correct.
- CStatement I is correct but statement II is incorrect
- DBoth statements I and statements II are correct.
Correct answer
C. Statement I is correct but statement II is incorrect
Step-by-step solution
Statement-I:
"The reaction of alcohol with carboxylic acid is carried out in presence of conc. (\mathrm{H}_2 \mathrm{SO}_4). This reaction is reversible and water is removed as soon as it is formed."
- This is Fischer esterification:
(\mathrm{RCOOH}+\mathrm{R}^{\prime} \mathrm{OH} \xrightarrow{\mathrm{H}_2 \mathrm{SO}_4} \mathrm{RCOOR} \mathrm{R}^{\prime}+\mathrm{H}_2 \mathrm{O})
- The reaction is reversible, and to drive it forward, water is removed.
Statement-I is correct.
Statement-II:
"Reaction of alcohol with acid chloride is carried in presence of base (pyridine) which do not neutralize HCl formed during the reaction."
- Reaction:
(\mathrm{RCOCl}+\mathrm{R}^{\prime} \mathrm{OH} \xrightarrow{\text{ pyridine }} \mathrm{RCOOR}^{\prime}+\mathrm{HCl})
- Here pyridine's role is to neutralize the HCl formed (otherwise HCl would protonate alcohol and stop the reaction).
- The statement says pyridine "does not neutralize HCl," which is wrong.
Statement-II is incorrect.