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NEET
Exam
NEET
Subject
Chemistry
Chapter
Carboxylic Acid Derivatives

NEET · Chemistry · Carboxylic Acid Derivatives

Match the reactions (in the given stoichiometry of the reactants)...

Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their products given in List-II and choose the correct option.

(
List-IList-II
(P)P_2 O_3+3 H_2 O → (1)P(O) (OCH3)Cl2</td></tr><tr><td>(Q)</td><td>P4+3NaOH+3H2O→</td><td>(2)</td><td>H3PO3</td></tr><tr><td>(R)</td><td>PCl5+CH3COOH→</td><td>(3)</td><td>PH3</td></tr><tr><td>(S)</td><td>H3PO2+2H2O+4AgNO3→</td><td>(4)</td><td>POCl3</td></tr><tr><td></td><td></td><td>(5)</td><td>H3PO4</td></tr></table>)\left(OCH_3\right) Cl_2</td></tr><tr><td>(Q)</td><td>P_4+3 NaOH+3 H_2 O → </td><td>(2)</td><td>H_3 PO_3</td></tr><tr><td>(R)</td><td>PCl_5+CH_3 COOH → </td><td>(3)</td><td>PH_3</td></tr><tr><td>(S)</td><td>H_3 PO_2+2 H_2 O+4 AgNO_3 → </td><td>(4)</td><td>POCl_3</td></tr><tr><td></td><td></td><td>(5)</td><td>H_3 PO_4</td></tr></table>)

Options

  1. AP→2;Q→3;R→1;S→5P \to 2; Q \to 3; R \to 1; S \to 5
  2. BP→3;Q→5;R→4;S→2P \to 3; Q \to 5; R \to 4; S \to 2
  3. CP→5;Q→2;R→1;S→3P \to 5; Q \to 2; R \to 1; S \to 3
  4. DP→2;Q→3;R→4;S→5P \to 2; Q \to 3; R \to 4; S \to 5

Correct answer

D. P→2;Q→3;R→4;S→5P \to 2; Q \to 3; R \to 4; S \to 5

Step-by-step solution

Phosphorus trioxide reacts with water to form phosphorous acid,

P2O3+3H2O→2H3PO3{P}_{2}{O}_{3} + 3{H}_{2}O \to 2{H}_{3}{PO}_{3}

When acetic acid is heated with phosphorus pentachloride, acetyl chloride is obtained. In this reaction, −COOH- COOH group is converted to −COCl- COCl group. The side products are phosphorus oxychloride and HClHCl.

PCl5+CH3COOH→CH3COCl+POCl3+HCl{PCl}_{5} + {CH}_{3}COOH \to {CH}_{3}COCl + {POCl}_{3} + HCl

P4{P}_{4} undergo disproportionation reaction with sodium hydroxide.

P4+3NaOH+3H2O→PH3+3NaH2PO2{P}_{4} + 3NaOH + 3{H}_{2}O\overset{}{\to}{PH}_{3} + 3{NaH}_{2}{PO}_{2}

Due to the presence two P−HP - H bonds, H3PO2{H}_{3}{PO}_{2} acts as reducing agent. It reduces Ag+{Ag}^{+} to AgAg.

H3PO2+H2O+AgNO3→H3PO4+HNO3+Ag↓{H}_{3}{PO}_{2} + {H}_{2}O + {AgNO}_{3} \to {H}_{3}{PO}_{4} + {HNO}_{3} + Ag ↓

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