NEETChemistryCarboxylic Acid Derivatives
Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their products given in List-II and choose the correct option. ( array |l|l|l|l| & List-I & & List-II (P) & P ₂ O ₃+3 H ₂ O & (1) & P ( O ) ( OCH ₃ ) Cl ₂ (Q) & P ₄+3 NaOH +3 H ₂ O & (2) & H ₃ PO ₃ (R) & PCl ₅+ CH ₃ COOH & (3) & PH ₃ (S) & H ₃ PO ₂+2 H ₂ O +4 AgNO ₃ & (4) & POCl ₃ & & (5) & H ₃ PO ₄ array )
Options
- AP → 2 ; Q → 3 ; R → 1 ; S → 5
- BP → 3 ; Q → 5 ; R → 4 ; S → 2
- CP → 5 ; Q → 2 ; R → 1 ; S → 3
- DP → 2 ; Q → 3 ; R → 4 ; S → 5
Correct answer
D. P → 2 ; Q → 3 ; R → 4 ; S → 5
Step-by-step solution
Phosphorus trioxide reacts with water to form phosphorous acid, P 2 O 3 + 3 H 2 O → 2 H 3 PO 3 When acetic acid is heated with phosphorus pentachloride, acetyl chloride is obtained. In this reaction, − COOH group is converted to − COCl group. The side products are phosphorus oxychloride and HCl . PCl 5 + CH 3 COOH → CH 3 COCl + POCl 3 + HCl P 4 undergo disproportionation reaction with sodium hydroxide. P 4 + 3 NaOH + 3 H 2 O → PH 3 + 3 NaH 2 PO 2 Due to the presence two P - H bonds, H 3 PO 2 acts as reducing agent.